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prove 1−sin(x)1+sin(x) =(sec(x)−tan(x))²

Solution

True

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Solution steps

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1−sin(x)1+sin(x) =(sec(x)−tan(x))²

Manipulating right side

(sec(x)−tan(x))²

Express with sin, cos

=(1−sin(x))²cos²(x)

Rewrite using trig identities

=1−sin(x)sin(x)+1

=1−sin(x)1+sin(x)

We showed that the two sides could take the same form

⇒ True

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

`a`	1
0	2`a`

6	−1
2	3

6	−1
2	3

6	−1
2	3

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