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(x^2+2x-1)-(2x^2-3x+6)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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simplify (x²+2x−1)−(2x²−3x+6)

Solution

−x²+5x−7

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Solution steps

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(x²+2x−1)−(2x²−3x+6)

Apply rule: (a)=a

(x²+2x−1)=x²+2x−1

=x²+2x−1−(2x²−3x+6)

Apply the distributive law: −(a−b)=−a+b

−(2x²−3x+6)=−2x²+3x−6

=x²+2x−1−2x²+3x−6

Group like terms

=x²−2x²+2x+3x−1−6

Add similar elements: x²−2x²=−x²

=−x²+2x+3x−1−6

Add similar elements: 2x+3x=5x

=−x²+5x−1−6

Subtract the numbers: −1−6=−7

=−x²+5x−7

Solve instead

f(x)=(x²+2x−1)−(2x²−3x+6)

ddx ((x²+2x−1)−(2x²−3x+6))

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

(x^2+2x-1)-(2x^2-3x+6)

Solution

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