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(2x-5)^{1/3}=3

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asymptotes 4x²−9y²−48x−72y+108=0

Solution

y=2(x−6)3 −4, y=−2(x−6)3 −4

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Hyperbola asymptotes

The asymptotes are the lines the hyperbola tends to at ±∞
For up-down hyperbola the asymptotes are y=±ab (x−h)+k

y=± ab (x−h)+k

Calculate Hyperbola properties

4x²−9y²−48x−72y+108=0: Up-down Hyperbola with (h, k)=(6, −4), a=2√3, b=3√3

y=2√33√3 (x−6)+(−4), y=−2√33√3 (x−6)+(−4)

Refine

y=2(x−6)3 −4, y=−2(x−6)3 −4

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

(2x-5)^{1/3}=3

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