prove (2tan(x))/(1+tan^2(x))=sin(2x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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prove sin(2x)sin(x) −cos(2x)cos(x) =sec(x)

Solution

True

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Solution steps

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sin(2x)sin(x) −cos(2x)cos(x) =sec(x)

Manipulating left side

sin(2x)sin(x) −cos(2x)cos(x)

Simplify −cos(2x)cos(x) +sin(2x)sin(x) : −cos(2x)sin(x)+sin(2x)cos(x)cos(x)sin(x)

=−cos(2x)sin(x)+cos(x)sin(2x)cos(x)sin(x)

Rewrite using trig identities

=1cos(x)

Rewrite using trig identities

sec(x)

We showed that the two sides could take the same form

⇒ True

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+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

prove (2tan(x))/(1+tan^2(x))=sin(2x)

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Solution steps

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