taylor sin(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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roots x²+2x+1

Solution

x=−1

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x²+2x+1

The roots are the intercepts with the x-axis (y=0)

x²+2x+1=0

Solve with the quadratic formula

x_{1, 2}=−2± √2²−4· 1· 12· 1

2²−4· 1· 1=0

x_{1, 2}=−2± √02· 1

x=−22· 1

−22· 1 =−1

x=−1

The solution to the quadratic equation is:

x=−1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

taylor sin(x)

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