What are the solutions to the equation x^2-5x-104=0 ?

The solutions to the equation x^2-5x-104=0 are x=13,x=-8

Find the zeros of x^2-5x-104=0

The zeros of x^2-5x-104=0 are x=13,x=-8

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x^{2} - 5 x - 104 = 0

x = 13, x = - 8

Solution steps

x^{2} - 5 x - 104 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 104 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 104) = 21

x_{1, 2} = \frac{- ( - 5 ) \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 21}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 21}{2 \cdot 1}

x = \frac{- ( - 5 ) + 21}{2 \cdot 1} : 13

x = \frac{- ( - 5 ) - 21}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 13, x = - 8

\frac{3}{5} - 2

40 x^{4} y^{6}

n^{2} + 3 n - 18 = 0

x^{2} - 22 x - 23 = 0

\frac{15 !}{4 ! ( 15 - 4 ) !}

What are the solutions to the equation x^2-5x-104=0 ?
The solutions to the equation x^2-5x-104=0 are x=13,x=-8
Find the zeros of x^2-5x-104=0
The zeros of x^2-5x-104=0 are x=13,x=-8