What are the solutions to the equation 4x^2+87=-36x ?

The solutions to the equation 4x^2+87=-36x are x=-9/2+isqrt(3/2),x=-9/2-isqrt(3/2)

Find the zeros of 4x^2+87=-36x

The zeros of 4x^2+87=-36x are x=-9/2+isqrt(3/2),x=-9/2-isqrt(3/2)

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4 x^{2} + 87 = - 36 x

x = - \frac{9}{2} + i \frac{3}{2}, x = - \frac{9}{2} - i \frac{3}{2}

Solution steps

4 x^{2} + 87 = - 36 x

Move

36 x

to the left side

4 x^{2} + 87 + 36 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 36 x + 87 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 4 \cdot 87}{2 \cdot 4}

Simplify

3 6^{2} - 4 \cdot 4 \cdot 87 : 46 i

x_{1, 2} = \frac{- 36 \pm 4 6 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 36 + 4 6 i}{2 \cdot 4}, x_{2} = \frac{- 36 - 4 6 i}{2 \cdot 4}

x = \frac{- 36 + 4 6 i}{2 \cdot 4} : - \frac{9}{2} + i \frac{3}{2}

x = \frac{- 36 - 4 6 i}{2 \cdot 4} : - \frac{9}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{9}{2} + i \frac{3}{2}, x = - \frac{9}{2} - i \frac{3}{2}

(x - 1)^{2} = - 4

\frac{4}{5} \cdot 8

4 x^{2} + 16 x + 12 = 0

- 2 x > 2

9 - 4 x \geq 5 or 4 (- 1 + x) - 6 \geq 2

What are the solutions to the equation 4x^2+87=-36x ?
The solutions to the equation 4x^2+87=-36x are x=-9/2+isqrt(3/2),x=-9/2-isqrt(3/2)
Find the zeros of 4x^2+87=-36x
The zeros of 4x^2+87=-36x are x=-9/2+isqrt(3/2),x=-9/2-isqrt(3/2)