What are the solutions to the equation 3(x+4)^2=10x+32 ?

The solutions to the equation 3(x+4)^2=10x+32 are x=-2,x=-8/3

Find the zeros of 3(x+4)^2=10x+32

The zeros of 3(x+4)^2=10x+32 are x=-2,x=-8/3

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3 (x + 4)^{2} = 10 x + 32

x = - 2, x = - \frac{8}{3}

Decimal Notation

x = - 2, x = - 2.66666 \dots

Solution steps

3 (x + 4)^{2} = 10 x + 32

Expand

3 (x + 4)^{2} : 3 x^{2} + 24 x + 48

3 x^{2} + 24 x + 48 = 10 x + 32

Move

32

to the left side

3 x^{2} + 24 x + 16 = 10 x

Move

10 x

to the left side

3 x^{2} + 14 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 \cdot 16}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 \cdot 16 = 2

x_{1, 2} = \frac{- 14 \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 14 + 2}{2 \cdot 3}, x_{2} = \frac{- 14 - 2}{2 \cdot 3}

x = \frac{- 14 + 2}{2 \cdot 3} : - 2

x = \frac{- 14 - 2}{2 \cdot 3} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = - 2, x = - \frac{8}{3}

\frac{x}{5} = \frac{10}{13}

4 y^{2} + 9 y + 5 = 0

u^{2} + 10 u + 25 = 0

(p + 1) (p + 3) = 0

12 x^{2} = 17 x + 5

What are the solutions to the equation 3(x+4)^2=10x+32 ?
The solutions to the equation 3(x+4)^2=10x+32 are x=-2,x=-8/3
Find the zeros of 3(x+4)^2=10x+32
The zeros of 3(x+4)^2=10x+32 are x=-2,x=-8/3