What are the solutions to the equation k^2+52k=-56 ?

The solutions to the equation k^2+52k=-56 are k=2(sqrt(155)-13),k=-2(13+sqrt(155))

Find the zeros of k^2+52k=-56

The zeros of k^2+52k=-56 are k=2(sqrt(155)-13),k=-2(13+sqrt(155))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

k^{2} + 52 k = - 56

k = 2 (155 - 13), k = - 2 (13 + 155)

Decimal Notation

k = - 1.10020 \dots, k = - 50.89979 \dots

Solution steps

k^{2} + 52 k = - 56

Move

56

to the left side

k^{2} + 52 k + 56 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 52 \pm 5 2 ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

5 2^{2} - 4 \cdot 1 \cdot 56 = 4155

k_{1, 2} = \frac{- 52 \pm 4 155}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 52 + 4 155}{2 \cdot 1}, k_{2} = \frac{- 52 - 4 155}{2 \cdot 1}

k = \frac{- 52 + 4 155}{2 \cdot 1} : 2 (155 - 13)

k = \frac{- 52 - 4 155}{2 \cdot 1} : - 2 (13 + 155)

The solutions to the quadratic equation are:

k = 2 (155 - 13), k = - 2 (13 + 155)

b^{6} - 64

i^{- 55}

\frac{1}{2} (20 x + 6) \geq x + 30

x^{2} + 5 x + 9 = 0

3 x^{3} - 6 x^{2} - 45 x

What are the solutions to the equation k^2+52k=-56 ?
The solutions to the equation k^2+52k=-56 are k=2(sqrt(155)-13),k=-2(13+sqrt(155))
Find the zeros of k^2+52k=-56
The zeros of k^2+52k=-56 are k=2(sqrt(155)-13),k=-2(13+sqrt(155))