What are the solutions to the equation x^2+5x-35=3x ?

The solutions to the equation x^2+5x-35=3x are x=5,x=-7

Find the zeros of x^2+5x-35=3x

The zeros of x^2+5x-35=3x are x=5,x=-7

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x^{2} + 5 x - 35 = 3 x

x = 5, x = - 7

Solution steps

x^{2} + 5 x - 35 = 3 x

Move

3 x

to the left side

x^{2} + 2 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 35) = 12

x_{1, 2} = \frac{- 2 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 12}{2 \cdot 1}, x_{2} = \frac{- 2 - 12}{2 \cdot 1}

x = \frac{- 2 + 12}{2 \cdot 1} : 5

x = \frac{- 2 - 12}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 5, x = - 7

x^{2} + 4 x + 4 = 9

- 2 + 3 x + 3 < 7

6 x^{2} + 7 x + 2 = 0

x^{- \frac{1}{4}}

(A^{1 + \frac{x}{y}})^{\frac{y}{x + y}}

What are the solutions to the equation x^2+5x-35=3x ?
The solutions to the equation x^2+5x-35=3x are x=5,x=-7
Find the zeros of x^2+5x-35=3x
The zeros of x^2+5x-35=3x are x=5,x=-7