What are the solutions to the equation 5a^2+12a-1=5a ?

The solutions to the equation 5a^2+12a-1=5a are a=(-7+sqrt(69))/(10),a=(-7-sqrt(69))/(10)

Find the zeros of 5a^2+12a-1=5a

The zeros of 5a^2+12a-1=5a are a=(-7+sqrt(69))/(10),a=(-7-sqrt(69))/(10)

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5 a^{2} + 12 a - 1 = 5 a

a = \frac{- 7 + 69}{10}, a = \frac{- 7 - 69}{10}

Decimal Notation

a = 0.13066 \dots, a = - 1.53066 \dots

Solution steps

5 a^{2} + 12 a - 1 = 5 a

Move

5 a

to the left side

5 a^{2} + 7 a - 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

7^{2} - 4 \cdot 5 (- 1) = 69

a_{1, 2} = \frac{- 7 \pm 69}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- 7 + 69}{2 \cdot 5}, a_{2} = \frac{- 7 - 69}{2 \cdot 5}

a = \frac{- 7 + 69}{2 \cdot 5} : \frac{- 7 + 69}{10}

a = \frac{- 7 - 69}{2 \cdot 5} : \frac{- 7 - 69}{10}

The solutions to the quadratic equation are:

a = \frac{- 7 + 69}{10}, a = \frac{- 7 - 69}{10}

\frac{20 x y ^{7}}{30 x y ^{8}}

1100 t = \frac{0.9}{1 + 20 e ^{- 2.25}}

\frac{1 + i}{2 - i} + \frac{- 3 - 2 i}{1 + 3 i}

∣ 2 x - 2 ∣ = ∣ - 6 ∣

3 - 3 i

What are the solutions to the equation 5a^2+12a-1=5a ?
The solutions to the equation 5a^2+12a-1=5a are a=(-7+sqrt(69))/(10),a=(-7-sqrt(69))/(10)
Find the zeros of 5a^2+12a-1=5a
The zeros of 5a^2+12a-1=5a are a=(-7+sqrt(69))/(10),a=(-7-sqrt(69))/(10)