What are the solutions to the equation x^2-4x=4 ?

The solutions to the equation x^2-4x=4 are x=2(1+sqrt(2)),x=2(1-sqrt(2))

Find the zeros of x^2-4x=4

The zeros of x^2-4x=4 are x=2(1+sqrt(2)),x=2(1-sqrt(2))

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x^{2} - 4 x = 4

x = 2 (1 + 2), x = 2 (1 - 2)

Solution steps

x^{2} - 4 x = 4

Move

4

to the left side

x^{2} - 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 4) = 42

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4 2}{2 \cdot 1} : 2 (1 + 2)

x = \frac{- ( - 4 ) - 4 2}{2 \cdot 1} : 2 (1 - 2)

The solutions to the quadratic equation are:

x = 2 (1 + 2), x = 2 (1 - 2)

2 (x + 1) - (x - 1) = 0

(x + 1) (x + 2) (x - 3) = (x - 2) (x + 1) (x + 1)

\frac{( 2 x ^{2} + 7 x + 3 )}{( 2 x ^{2} - 7 x - 4 )}

x^{4} + 2 x^{3} - 7 x^{2} - 20 x - 12

6 b < - 18

What are the solutions to the equation x^2-4x=4 ?
The solutions to the equation x^2-4x=4 are x=2(1+sqrt(2)),x=2(1-sqrt(2))
Find the zeros of x^2-4x=4
The zeros of x^2-4x=4 are x=2(1+sqrt(2)),x=2(1-sqrt(2))