What is the answer to (x+1)(x+2)(x-3)=(x-2)(x+1)(x+1) ?

The answer to (x+1)(x+2)(x-3)=(x-2)(x+1)(x+1) is x=-1

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(x+1)(x+2)(x-3)=(x-2)(x+1)(x+1)

(x + 1) (x + 2) (x - 3) = (x - 2) (x + 1) (x + 1)

x = - 1

Solution steps

(x + 1) (x + 2) (x - 3) = (x - 2) (x + 1) (x + 1)

Expand

(x + 1) (x + 2) : x^{2} + 3 x + 2

(x^{2} + 3 x + 2) (x - 3) = (x - 2) (x + 1) (x + 1)

Expand

(x^{2} + 3 x + 2) (x - 3) : x^{3} - 7 x - 6

x^{3} - 7 x - 6 = (x - 2) (x + 1) (x + 1)

Expand

(x - 2) (x + 1) (x + 1) : x^{3} - 3 x - 2

x^{3} - 7 x - 6 = x^{3} - 3 x - 2

Move

6

to the right side

x^{3} - 7 x = x^{3} - 3 x + 4

Subtract

x^{3} - 3 x

from both sides

x^{3} - 7 x - (x^{3} - 3 x) = x^{3} - 3 x + 4 - (x^{3} - 3 x)

Simplify

- 4 x = 4

Divide both sides by

- 4

x = - 1

\frac{( 2 x ^{2} + 7 x + 3 )}{( 2 x ^{2} - 7 x - 4 )}

x^{4} + 2 x^{3} - 7 x^{2} - 20 x - 12

6 b < - 18

x^{2} + 10 x + 26 = 0

7^{3}

What is the answer to (x+1)(x+2)(x-3)=(x-2)(x+1)(x+1) ?
The answer to (x+1)(x+2)(x-3)=(x-2)(x+1)(x+1) is x=-1
Solve for x: (x+1)(x+2)(x-3)=(x-2)(x+1)(x+1)
The solution is x=-1