What are the solutions to the equation 14a^2-a=5a^2-5a ?

The solutions to the equation 14a^2-a=5a^2-5a are a=0,a=-4/9

Find the zeros of 14a^2-a=5a^2-5a

The zeros of 14a^2-a=5a^2-5a are a=0,a=-4/9

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14 a^{2} - a = 5 a^{2} - 5 a

a = 0, a = - \frac{4}{9}

Decimal Notation

a = 0, a = - 0.44444 \dots

Solution steps

14 a^{2} - a = 5 a^{2} - 5 a

Move

5 a

to the left side

14 a^{2} + 4 a = 5 a^{2}

Move

5 a^{2}

to the left side

9 a^{2} + 4 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

4^{2} - 4 \cdot 9 \cdot 0 = 4

a_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 9}

Separate the solutions

a_{1} = \frac{- 4 + 4}{2 \cdot 9}, a_{2} = \frac{- 4 - 4}{2 \cdot 9}

a = \frac{- 4 + 4}{2 \cdot 9} : 0

a = \frac{- 4 - 4}{2 \cdot 9} : - \frac{4}{9}

The solutions to the quadratic equation are:

a = 0, a = - \frac{4}{9}

\frac{2 x ^{2} - 10 x}{x ^{2} - 4 x - 5}

\frac{36}{64}

\frac{- 21}{- 7}

- \frac{x}{4} < 12

5 x (2 x + 1) - 3 (2 x + 1) = 0

What are the solutions to the equation 14a^2-a=5a^2-5a ?
The solutions to the equation 14a^2-a=5a^2-5a are a=0,a=-4/9
Find the zeros of 14a^2-a=5a^2-5a
The zeros of 14a^2-a=5a^2-5a are a=0,a=-4/9