What are the solutions to the equation k^2=0.49 ?

The solutions to the equation k^2=0.49 are k= 7/10 ,k=-7/10

Find the zeros of k^2=0.49

The zeros of k^2=0.49 are k= 7/10 ,k=-7/10

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k^{2} = 0.49

k = \frac{7}{10}, k = - \frac{7}{10}

Solution steps

k^{2} = 0.49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 0.49, k = - 0.49

0.49 = \frac{7}{10}

- 0.49 = - \frac{7}{10}

k = \frac{7}{10}, k = - \frac{7}{10}

x^{2} + \frac{5}{2} x + 1 = 0

- p - 4 p = 0

\frac{4}{b - 8} + \frac{7}{b ^{2} - 64}

x^{10}

n^{4} - 100

What are the solutions to the equation k^2=0.49 ?
The solutions to the equation k^2=0.49 are k= 7/10 ,k=-7/10
Find the zeros of k^2=0.49
The zeros of k^2=0.49 are k= 7/10 ,k=-7/10