What are the solutions to the equation x^2-14x-51=0 ?

The solutions to the equation x^2-14x-51=0 are x=17,x=-3

Find the zeros of x^2-14x-51=0

The zeros of x^2-14x-51=0 are x=17,x=-3

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x^{2} - 14 x - 51 = 0

x = 17, x = - 3

Solution steps

x^{2} - 14 x - 51 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 51 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 51) = 20

x_{1, 2} = \frac{- ( - 14 ) \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 20}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 20}{2 \cdot 1}

x = \frac{- ( - 14 ) + 20}{2 \cdot 1} : 17

x = \frac{- ( - 14 ) - 20}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 17, x = - 3

3 x^{2} + 2 x - 65 = 0

x^{4} + 8 x^{2} + 16

\frac{14 x ^{6} y ^{5}}{7 x ^{8} y ^{8}}

(\frac{1}{x})^{3}

3 z^{2} + z - 2

What are the solutions to the equation x^2-14x-51=0 ?
The solutions to the equation x^2-14x-51=0 are x=17,x=-3
Find the zeros of x^2-14x-51=0
The zeros of x^2-14x-51=0 are x=17,x=-3