What are the solutions to the equation x^2-3x+16=2x^2-3x ?

The solutions to the equation x^2-3x+16=2x^2-3x are x=4,x=-4

Find the zeros of x^2-3x+16=2x^2-3x

The zeros of x^2-3x+16=2x^2-3x are x=4,x=-4

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x^{2} - 3 x + 16 = 2 x^{2} - 3 x

x = 4, x = - 4

Solution steps

x^{2} - 3 x + 16 = 2 x^{2} - 3 x

Move

16

to the right side

x^{2} - 3 x = 2 x^{2} - 3 x - 16

Move

3 x

to the left side

x^{2} = 2 x^{2} - 16

Move

2 x^{2}

to the left side

- x^{2} = - 16

Divide both sides by

- 1

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

x^{2} - 10 x + 25 = 1

- 3 x^{2} + 7 x - 3 = 0

x^{2} - 2 x - 23 = 0

5 - 5 x^{2} = - 230

2 x^{2} - 15 x + 7 = 0

What are the solutions to the equation x^2-3x+16=2x^2-3x ?
The solutions to the equation x^2-3x+16=2x^2-3x are x=4,x=-4
Find the zeros of x^2-3x+16=2x^2-3x
The zeros of x^2-3x+16=2x^2-3x are x=4,x=-4