What are the solutions to the equation x^2-10x+25=1 ?

The solutions to the equation x^2-10x+25=1 are x=6,x=4

Find the zeros of x^2-10x+25=1

The zeros of x^2-10x+25=1 are x=6,x=4

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x^{2} - 10 x + 25 = 1

x = 6, x = 4

Solution steps

x^{2} - 10 x + 25 = 1

Move

1

to the left side

x^{2} - 10 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

x_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

x = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 6, x = 4

- 3 x^{2} + 7 x - 3 = 0

x^{2} - 2 x - 23 = 0

5 - 5 x^{2} = - 230

2 x^{2} - 15 x + 7 = 0

(x + 4)^{2} - 25 = 0

What are the solutions to the equation x^2-10x+25=1 ?
The solutions to the equation x^2-10x+25=1 are x=6,x=4
Find the zeros of x^2-10x+25=1
The zeros of x^2-10x+25=1 are x=6,x=4