What are the solutions to the equation 8x^2-14=-11 ?

The solutions to the equation 8x^2-14=-11 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))

Find the zeros of 8x^2-14=-11

The zeros of 8x^2-14=-11 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))

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8 x^{2} - 14 = - 11

x = \frac{3}{2 2}, x = - \frac{3}{2 2}

Decimal Notation

x = 0.61237 \dots, x = - 0.61237 \dots

Solution steps

8 x^{2} - 14 = - 11

Move

14

to the right side

8 x^{2} = 3

Divide both sides by

8

x^{2} = \frac{3}{8}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{8}, x = - \frac{3}{8}

\frac{3}{8} = \frac{3}{2 2}

- \frac{3}{8} = - \frac{3}{2 2}

x = \frac{3}{2 2}, x = - \frac{3}{2 2}

\frac{( 2 x - 3 )}{( x + 1 )} \leq 1

- \frac{3}{4} + \frac{7}{2} = - 43 + 27

(- 1)^{0}

3 hk - 2 k - 12 h + 8

\frac{x - 4}{2} - \frac{3 x + 1}{4} \leq \frac{- x}{8}

What are the solutions to the equation 8x^2-14=-11 ?
The solutions to the equation 8x^2-14=-11 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))
Find the zeros of 8x^2-14=-11
The zeros of 8x^2-14=-11 are x=(sqrt(3))/(2sqrt(2)),x=-(sqrt(3))/(2sqrt(2))