What are the solutions to the equation 43-x^2=12 ?

The solutions to the equation 43-x^2=12 are x=sqrt(31),x=-sqrt(31)

Find the zeros of 43-x^2=12

The zeros of 43-x^2=12 are x=sqrt(31),x=-sqrt(31)

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43 - x^{2} = 12

x = 31, x = - 31

Decimal Notation

x = 5.56776 \dots, x = - 5.56776 \dots

Solution steps

43 - x^{2} = 12

Move

43

to the right side

- x^{2} = - 31

Divide both sides by

- 1

x^{2} = 31

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 31, x = - 31

\frac{( - a b ^{2} c ) ^{- 1}}{a ^{- 2} b c ^{- 1}}

x^{3} - 4 x^{2} - 4 x + 16

4 n + 2 = 6

11 (n - 1) + 35 = 3 n

9 x^{2} + 49 = 0

What are the solutions to the equation 43-x^2=12 ?
The solutions to the equation 43-x^2=12 are x=sqrt(31),x=-sqrt(31)
Find the zeros of 43-x^2=12
The zeros of 43-x^2=12 are x=sqrt(31),x=-sqrt(31)