What are the solutions to the equation -0.2x^2+86x-5040=0 ?

The solutions to the equation -0.2x^2+86x-5040=0 are x=70,x=360

Find the zeros of -0.2x^2+86x-5040=0

The zeros of -0.2x^2+86x-5040=0 are x=70,x=360

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- 0.2 x^{2} + 86 x - 5040 = 0

x = 70, x = 360

Solution steps

- 0.2 x^{2} + 86 x - 5040 = 0

Multiply both sides by

10

- 2 x^{2} + 860 x - 50400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 860 \pm 86 0 ^{2} - 4 ( - 2 ) ( - 50400 )}{2 ( - 2 )}

86 0^{2} - 4 (- 2) (- 50400) = 580

x_{1, 2} = \frac{- 860 \pm 580}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 860 + 580}{2 ( - 2 )}, x_{2} = \frac{- 860 - 580}{2 ( - 2 )}

x = \frac{- 860 + 580}{2 ( - 2 )} : 70

x = \frac{- 860 - 580}{2 ( - 2 )} : 360

The solutions to the quadratic equation are:

x = 70, x = 360

0. 1^{4}

y^{2} = 7

\frac{1}{2} (\frac{1}{2})

x^{2} + 16 x + 58 = 0

x^{2} = 512

What are the solutions to the equation -0.2x^2+86x-5040=0 ?
The solutions to the equation -0.2x^2+86x-5040=0 are x=70,x=360
Find the zeros of -0.2x^2+86x-5040=0
The zeros of -0.2x^2+86x-5040=0 are x=70,x=360