4+n/3 <= 6

Solution

4 + \frac{n}{3} \leq 6

n \leq 6

Interval Notation

(- \infty, 6]

Solution steps

4 + \frac{n}{3} \leq 6

Move

4

to the right side

\frac{n}{3} \leq 2

Multiply both sides by

3

n \leq 6

2 x + 7 \leq 31

(\frac{- 2 a ^{3} b ^{2} c ^{0}}{3 a ^{2} b ^{3} c ^{7}})^{- 2}

5 x^{2} + 6 x - 7 = 0

\frac{( 4 x ^{- 3} y ^{5} ) ^{3}}{( 16 x ^{2} y ^{- 2} ) ^{- 4}}

x^{2} - 5 x + 15 = x (x - 3) - 14 + 5 (x - 2) + 3 (13 - 2 x)