What are the solutions to the equation x^2+7x-1=0 ?

The solutions to the equation x^2+7x-1=0 are x=(-7+sqrt(53))/2 ,x=(-7-sqrt(53))/2

Find the zeros of x^2+7x-1=0

The zeros of x^2+7x-1=0 are x=(-7+sqrt(53))/2 ,x=(-7-sqrt(53))/2

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x^{2} + 7 x - 1 = 0

x = \frac{- 7 + 53}{2}, x = \frac{- 7 - 53}{2}

Decimal Notation

x = 0.14005 \dots, x = - 7.14005 \dots

Solution steps

x^{2} + 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 1) = 53

x_{1, 2} = \frac{- 7 \pm 53}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 53}{2 \cdot 1}, x_{2} = \frac{- 7 - 53}{2 \cdot 1}

x = \frac{- 7 + 53}{2 \cdot 1} : \frac{- 7 + 53}{2}

x = \frac{- 7 - 53}{2 \cdot 1} : \frac{- 7 - 53}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 53}{2}, x = \frac{- 7 - 53}{2}

x^{2} - 16 x + 58 = 0

4 x^{2} + 4 x - 168 = 0

\frac{y ^{2}}{y ^{- 5}}

3 y^{2} - 7 y + 2 = 0

\frac{1}{4} - 3

What are the solutions to the equation x^2+7x-1=0 ?
The solutions to the equation x^2+7x-1=0 are x=(-7+sqrt(53))/2 ,x=(-7-sqrt(53))/2
Find the zeros of x^2+7x-1=0
The zeros of x^2+7x-1=0 are x=(-7+sqrt(53))/2 ,x=(-7-sqrt(53))/2