What are the solutions to the equation 16x^2-48x+37=0 ?

The solutions to the equation 16x^2-48x+37=0 are x= 3/2+i 1/4 ,x= 3/2-i 1/4

Find the zeros of 16x^2-48x+37=0

The zeros of 16x^2-48x+37=0 are x= 3/2+i 1/4 ,x= 3/2-i 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 x^{2} - 48 x + 37 = 0

x = \frac{3}{2} + i \frac{1}{4}, x = \frac{3}{2} - i \frac{1}{4}

Solution steps

16 x^{2} - 48 x + 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 16 \cdot 37}{2 \cdot 16}

Simplify

(- 48)^{2} - 4 \cdot 16 \cdot 37 : 8 i

x_{1, 2} = \frac{- ( - 48 ) \pm 8 i}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 8 i}{2 \cdot 16}, x_{2} = \frac{- ( - 48 ) - 8 i}{2 \cdot 16}

x = \frac{- ( - 48 ) + 8 i}{2 \cdot 16} : \frac{3}{2} + i \frac{1}{4}

x = \frac{- ( - 48 ) - 8 i}{2 \cdot 16} : \frac{3}{2} - i \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{1}{4}, x = \frac{3}{2} - i \frac{1}{4}

x^{2} - \frac{3}{5} x = 60

5 (x - 3) = 10 x - 15

\frac{x - 7}{5} - \frac{x - 11}{6} + \frac{x - 10}{7} = 2

- 6 \leq x \leq 6

\frac{2}{p ^{2} + pq} + \frac{3}{pq - q ^{2}}

What are the solutions to the equation 16x^2-48x+37=0 ?
The solutions to the equation 16x^2-48x+37=0 are x= 3/2+i 1/4 ,x= 3/2-i 1/4
Find the zeros of 16x^2-48x+37=0
The zeros of 16x^2-48x+37=0 are x= 3/2+i 1/4 ,x= 3/2-i 1/4