What are the solutions to the equation 4x^2+1=3x ?

The solutions to the equation 4x^2+1=3x are x= 3/8+i(sqrt(7))/8 ,x= 3/8-i(sqrt(7))/8

Find the zeros of 4x^2+1=3x

The zeros of 4x^2+1=3x are x= 3/8+i(sqrt(7))/8 ,x= 3/8-i(sqrt(7))/8

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4 x^{2} + 1 = 3 x

x = \frac{3}{8} + i \frac{7}{8}, x = \frac{3}{8} - i \frac{7}{8}

Solution steps

4 x^{2} + 1 = 3 x

Move

3 x

to the left side

4 x^{2} + 1 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

Simplify

(- 3)^{2} - 4 \cdot 4 \cdot 1 : 7 i

x_{1, 2} = \frac{- ( - 3 ) \pm 7 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7 i}{2 \cdot 4}, x_{2} = \frac{- ( - 3 ) - 7 i}{2 \cdot 4}

x = \frac{- ( - 3 ) + 7 i}{2 \cdot 4} : \frac{3}{8} + i \frac{7}{8}

x = \frac{- ( - 3 ) - 7 i}{2 \cdot 4} : \frac{3}{8} - i \frac{7}{8}

The solutions to the quadratic equation are:

x = \frac{3}{8} + i \frac{7}{8}, x = \frac{3}{8} - i \frac{7}{8}

- 3 x^{2} - 4 x - 8 = 0

x^{2} + 2 ∣ x - 3 ∣ - 9 > 0

16 x^{2} + 24 x y + 9 y^{2}

x^{4} y^{3} \cdot (2 y^{2})^{0}

x^{2} - 3 x = (x + 3) (x - 4)

What are the solutions to the equation 4x^2+1=3x ?
The solutions to the equation 4x^2+1=3x are x= 3/8+i(sqrt(7))/8 ,x= 3/8-i(sqrt(7))/8
Find the zeros of 4x^2+1=3x
The zeros of 4x^2+1=3x are x= 3/8+i(sqrt(7))/8 ,x= 3/8-i(sqrt(7))/8