What are the solutions to the equation 1=x^2 ?

The solutions to the equation 1=x^2 are x=1,x=-1

Find the zeros of 1=x^2

The zeros of 1=x^2 are x=1,x=-1

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1 = x^{2}

x = 1, x = - 1

Solution steps

1 = x^{2}

Switch sides

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

- 5 6^{2} + 3 3^{2} = c^{2}

(\frac{e}{10})^{1}

y^{2} + 2 y = 35

\frac{5}{6 x ^{7} y ^{4}} \cdot \frac{5}{3 x ^{6} y ^{3}}

- 3 (w + 5) + 5 w = 2 (w - 6)

What are the solutions to the equation 1=x^2 ?
The solutions to the equation 1=x^2 are x=1,x=-1
Find the zeros of 1=x^2
The zeros of 1=x^2 are x=1,x=-1