What is (-2y^3z^{-2})^4+4(z^{-4}y^6)^2 ?

The solution to (-2y^3z^{-2})^4+4(z^{-4}y^6)^2 is (20y^{12})/(z^8)

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simplify (-2y^3z^{-2})^4+4(z^{-4}y^6)^2

simplify

(- 2 y^{3} z^{- 2})^{4} + 4 (z^{- 4} y^{6})^{2}

\frac{20 y ^{12}}{z ^{8}}

Solution steps

(- 2 y^{3} z^{- 2})^{4} + 4 (z^{- 4} y^{6})^{2}

(- 2 y^{3} z^{- 2})^{4} = \frac{16 y ^{12}}{z ^{8}}

(z^{- 4} y^{6})^{2} = \frac{y ^{12}}{z ^{8}}

= \frac{16 y ^{12}}{z ^{8}} + 4 \cdot \frac{y ^{12}}{z ^{8}}

Simplify

4 \cdot \frac{y ^{12}}{z ^{8}} : \frac{4 y ^{12}}{z ^{8}}

= \frac{16 y ^{12}}{z ^{8}} + \frac{4 y ^{12}}{z ^{8}}

Join

\frac{16 y ^{12}}{z ^{8}} + \frac{4 y ^{12}}{z ^{8}} : \frac{20 y ^{12}}{z ^{8}}

= \frac{20 y ^{12}}{z ^{8}}

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What is (-2y^3z^{-2})^4+4(z^{-4}y^6)^2 ?
The solution to (-2y^3z^{-2})^4+4(z^{-4}y^6)^2 is (20y^{12})/(z^8)