What is (27-19i)/(-3-10i) ?

The solution to (27-19i)/(-3-10i) is 1+3i

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simplify (27-19i)/(-3-10i)

simplify

\frac{27 - 19 i}{- 3 - 10 i}

1 + 3 i

Solution steps

\frac{27 - 19 i}{- 3 - 10 i}

Multiply by the conjugate

\frac{- 3 + 10 i}{- 3 + 10 i}

= \frac{( 27 - 19 i ) ( - 3 + 10 i )}{( - 3 - 10 i ) ( - 3 + 10 i )}

Simplify

\frac{( 27 - 19 i ) ( - 3 + 10 i )}{( - 3 - 10 i ) ( - 3 + 10 i )} : \frac{109 + 327 i}{109}

= \frac{109 + 327 i}{109}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{109}{109} + \frac{327}{109} i

Simplify

\frac{109}{109} + \frac{327}{109} i : 1 + 3 i

= 1 + 3 i

\frac{x ^{3} + 3 x ^{2} + 3 x + 1}{x + 1}

x^{3} + x^{2} - 10 x + 8

8 \times \frac{2}{3}

12. 5^{2}

\frac{x + 7}{7 x + 35} \cdot \frac{x ^{2} - 3 x - 40}{x - 8}