What is expand (x+2)(x+1)(x-3) ?

The solution to expand (x+2)(x+1)(x-3) is x^3-7x-6

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expand (x+2)(x+1)(x-3)

expand

(x + 2) (x + 1) (x - 3)

x^{3} - 7 x - 6

Solution steps

(x + 2) (x + 1) (x - 3)

Expand

(x + 2) (x + 1) (x - 3) : (x^{2} + 3 x + 2) (x - 3)

= (x^{2} + 3 x + 2) (x - 3)

Distribute parentheses

= x^{2} x + x^{2} (- 3) + 3 xx + 3 x (- 3) + 2 x + 2 (- 3)

Simplify

x^{2} x + x^{2} (- 3) + 3 xx + 3 x (- 3) + 2 x + 2 (- 3) : x^{3} - 7 x - 6

= x^{3} - 7 x - 6

\frac{x}{x ^{2} - 64} - \frac{7}{4 x ^{2} + 32 x}

\frac{3}{3 x}

lo g_{\frac{1}{2}} (256)

\frac{512}{3}

What is expand (x+2)(x+1)(x-3) ?
The solution to expand (x+2)(x+1)(x-3) is x^3-7x-6