What is 4x-2x^2>= 0 ?

The solution to 4x-2x^2>= 0 is 0<= x<= 2

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4x-2x^2>= 0

4 x - 2 x^{2} \geq 0

0 \leq x \leq 2

Interval Notation

[0, 2]

Solution steps

4 x - 2 x^{2} \geq 0

Rewrite in standard form

- x^{2} + 2 x \geq 0

Factor

- x^{2} + 2 x : - x (x - 2)

- x (x - 2) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- x (x - 2)) (- 1) \leq 0 \cdot (- 1)

Simplify

x (x - 2) \leq 0

Identify the intervals

0 \leq x \leq 2

25 + 36

3.5 n - 1356 - 1.28 \cdot 2.916 n > 0

4 x^{2} + 8 x - 10 = 0

7 x + 55 \geq 160

p (p^{- 7} q^{3})^{- 2} q^{- 3}