What are the solutions to the equation 4x^2+8x-10=0 ?

The solutions to the equation 4x^2+8x-10=0 are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2

Find the zeros of 4x^2+8x-10=0

The zeros of 4x^2+8x-10=0 are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2

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4 x^{2} + 8 x - 10 = 0

x = \frac{- 2 + 14}{2}, x = - \frac{2 + 14}{2}

Solution steps

4 x^{2} + 8 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 ( - 10 )}{2 \cdot 4}

8^{2} - 4 \cdot 4 (- 10) = 414

x_{1, 2} = \frac{- 8 \pm 4 14}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4 14}{2 \cdot 4}, x_{2} = \frac{- 8 - 4 14}{2 \cdot 4}

x = \frac{- 8 + 4 14}{2 \cdot 4} : \frac{- 2 + 14}{2}

x = \frac{- 8 - 4 14}{2 \cdot 4} : - \frac{2 + 14}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 14}{2}, x = - \frac{2 + 14}{2}

7 x + 55 \geq 160

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12 - 2 ∣ x + 4 ∣ > 6

What are the solutions to the equation 4x^2+8x-10=0 ?
The solutions to the equation 4x^2+8x-10=0 are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2
Find the zeros of 4x^2+8x-10=0
The zeros of 4x^2+8x-10=0 are x=(-2+sqrt(14))/2 ,x=-(2+sqrt(14))/2