What is (36x^5+9x^2)/(3x) ?

The solution to (36x^5+9x^2)/(3x) is 3x(4x^3+1)

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simplify (36x^5+9x^2)/(3x)

simplify

\frac{36 x ^{5} + 9 x ^{2}}{3 x}

3 x (4 x^{3} + 1)

Solution steps

\frac{36 x ^{5} + 9 x ^{2}}{3 x}

Factor

36 x^{5} + 9 x^{2} : 9 x^{2} (4 x^{3} + 1)

= \frac{9 x ^{2} ( 4 x ^{3} + 1 )}{3 x}

Factor the number:

9 = 3 \cdot 3

= \frac{3 \cdot 3 x ^{2} ( 4 x ^{3} + 1 )}{3 x}

Cancel the common factor:

3

= \frac{3 x ^{2} ( 4 x ^{3} + 1 )}{x}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{3 xx ( 4 x ^{3} + 1 )}{x}

Cancel the common factor:

x

= 3 x (4 x^{3} + 1)

\frac{\frac{21 m ^{7}}{8 n ^{3}}}{\frac{7 m ^{8}}{12 n ^{4}}}

- i^{5}

\frac{x + 2}{3 x} + \frac{x ^{2} - 2}{5 x ^{2}} + \frac{2 - x ^{3}}{9 x ^{3}}

1.5 \times 3

⌊ 0.5 ⌋