What are the solutions to the equation (2x+3)^2-13=0 ?

The solutions to the equation (2x+3)^2-13=0 are x=(sqrt(13)-3)/2 ,x=(-sqrt(13)-3)/2

Find the zeros of (2x+3)^2-13=0

The zeros of (2x+3)^2-13=0 are x=(sqrt(13)-3)/2 ,x=(-sqrt(13)-3)/2

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(2 x + 3)^{2} - 13 = 0

x = \frac{13 - 3}{2}, x = \frac{- 13 - 3}{2}

Solution steps

(2 x + 3)^{2} - 13 = 0

Move

13

to the right side

(2 x + 3)^{2} = 13

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 3 = 13 : x = \frac{13 - 3}{2}

Solve

2 x + 3 = - 13 : x = \frac{- 13 - 3}{2}

The solutions to the quadratic equation are:

x = \frac{13 - 3}{2}, x = \frac{- 13 - 3}{2}

- 16 + 5 x = - 7 (- 6 + 8 x) + 3

r (14 r + 15) = 0

3^{3}

1 < \frac{∣ x - 2 ∣}{∣ x + 3 ∣}

∣ 2 k - 1 ∣ \leq 2

What are the solutions to the equation (2x+3)^2-13=0 ?
The solutions to the equation (2x+3)^2-13=0 are x=(sqrt(13)-3)/2 ,x=(-sqrt(13)-3)/2
Find the zeros of (2x+3)^2-13=0
The zeros of (2x+3)^2-13=0 are x=(sqrt(13)-3)/2 ,x=(-sqrt(13)-3)/2