What is (1/4-3m)(3m+1/4) ?

The solution to (1/4-3m)(3m+1/4) is ((-12m+1)(12m+1))/(16)

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simplify (1/4-3m)(3m+1/4)

simplify

(\frac{1}{4} - 3 m) (3 m + \frac{1}{4})

\frac{( - 12 m + 1 ) ( 12 m + 1 )}{16}

Solution steps

(\frac{1}{4} - 3 m) (3 m + \frac{1}{4})

Join

\frac{1}{4} - 3 m : \frac{- 12 m + 1}{4}

= \frac{- 12 m + 1}{4} (3 m + \frac{1}{4})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 12 m + 1 ) ( 3 m + \frac{1}{4} )}{4}

Simplify

(- 12 m + 1) (3 m + \frac{1}{4}) : \frac{( - 12 m + 1 ) ( 12 m + 1 )}{4}

= \frac{\frac{( - 12 m + 1 ) ( 12 m + 1 )}{4}}{4}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - 12 m + 1 ) ( 12 m + 1 )}{4 \cdot 4}

Multiply the numbers:

4 \cdot 4 = 16

= \frac{( - 12 m + 1 ) ( 12 m + 1 )}{16}

\frac{4 x - 1}{( x - 2 ) ( x + 3 )}

(x^{2} + a x - 1 - x^{2} - a x + 1) \cdot (x^{2} + a x - 1 + x^{2} - a x + 1)

(\frac{2 x}{3} - \frac{2}{y})^{4}

(2 - 3 i)^{5}

e^{t} (cos (2 t) - sin (2 t))^{2}

What is (1/4-3m)(3m+1/4) ?
The solution to (1/4-3m)(3m+1/4) is ((-12m+1)(12m+1))/(16)