What is (d^2)/(dx^2)((y)(4y+1)) ?

The answer to (d^2)/(dx^2)((y)(4y+1)) is 8((dy)/(dx)^2+(d^2y)/(dx^2)y)+(d^2y)/(dx^2)

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(d^2)/(dx^2)((y)(4y+1))

\frac{d ^{2}}{d x ^{2}} ((y) (4 y + 1))

8 (\frac{d y}{d x}^{2} + \frac{d ^{2} y}{d x ^{2}} y) + \frac{d ^{2} y}{d x ^{2}}

Solution steps

\frac{d ^{2}}{d x ^{2}} ((y) (4 y + 1))

\frac{d}{d x} (y (4 y + 1)) = 8 y \frac{d y}{d x} + \frac{d y}{d x}

= \frac{d}{d x} (8 y \frac{d y}{d x} + \frac{d y}{d x})

\frac{d}{d x} (8 y \frac{d y}{d x} + \frac{d y}{d x}) = 8 (\frac{d y}{d x}^{2} + \frac{d ^{2} y}{d x ^{2}} y) + \frac{d ^{2} y}{d x ^{2}}

= 8 (\frac{d y}{d x}^{2} + \frac{d ^{2} y}{d x ^{2}} y) + \frac{d ^{2} y}{d x ^{2}}

\frac{13 x + 6}{( x + 1 ) ( x - 1 )}

(\frac{1}{x} + x) \cdot (1 - \frac{1}{x + 1})

\frac{\partial}{\partial x} ((z) (x^{2} + 3 x y - y^{2}))

sin (a) (1 - cos (b)) + sin (b) (1 - cos (a))

(3 x - 4 y + 4 = 0,) (9 x - 12 y - 4 = 0)

What is (d^2)/(dx^2)((y)(4y+1)) ?
The answer to (d^2)/(dx^2)((y)(4y+1)) is 8((dy)/(dx)^2+(d^2y)/(dx^2)y)+(d^2y)/(dx^2)