What is expand (2x+5)/((x^2+2)(x+1)'') ?

The solution to expand (2x+5)/((x^2+2)(x+1)'') is (2x+5)/(x^2(x+1)''+2(x+1)'')

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expand (2x+5)/((x^2+2)(x+1)'')

expand

\frac{2 x + 5}{( x ^{2} + 2 ) ( x + 1 ) ^{''}}

\frac{2 x + 5}{x ^{2} ( x + 1 ) '' + 2 ( x + 1 ) ''}

Solution steps

\frac{2 x + 5}{( x ^{2} + 2 ) ( x + 1 ) ^{''}}

Expand

(x^{2} + 2) (x + 1)^{''} : x^{2} (x + 1)^{''} + 2 (x + 1)^{''}

= \frac{2 x + 5}{x ^{2} ( x + 1 ) ^{''} + 2 ( x + 1 ) ^{''}}

(2 x + 1)!

(\frac{x ^{2} y ^{3}}{3} - 6) (\frac{x ^{2} y ^{3}}{3} + 8)

(0.6 \times \frac{20}{7} + \frac{3}{14}) \times 1.5

(2 + 4 sin (θ))^{2}

(x y - x^{2}) (x y + x^{2})

What is expand (2x+5)/((x^2+2)(x+1)'') ?
The solution to expand (2x+5)/((x^2+2)(x+1)'') is (2x+5)/(x^2(x+1)''+2(x+1)'')