What is expand (s-1)/(s(s+1)(s+2)) ?

The solution to expand (s-1)/(s(s+1)(s+2)) is (s-1)/(s^3+3s^2+2s)

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expand (s-1)/(s(s+1)(s+2))

expand

\frac{s - 1}{s ( s + 1 ) ( s + 2 )}

\frac{s - 1}{s ^{3} + 3 s ^{2} + 2 s}

Solution steps

\frac{s - 1}{s ( s + 1 ) ( s + 2 )}

Expand

s (s + 1) (s + 2) : s^{3} + 3 s^{2} + 2 s

= \frac{s - 1}{s ^{3} + 3 s ^{2} + 2 s}

3 cos (t) h \cdot (t - π)

2 \cdot (ln (x) - (\frac{1}{4}) \cdot e^{x}) \cdot (\frac{1}{x} - (\frac{1}{4}) \cdot e^{x})

(cos (θ) - x)^{2} + sin^{2} (θ)

\frac{2 x + 1}{x ( x + 1 ) ( x ^{2} + 4 x + 6 )}

What is expand (s-1)/(s(s+1)(s+2)) ?
The solution to expand (s-1)/(s(s+1)(s+2)) is (s-1)/(s^3+3s^2+2s)