What is expand 3cos(t)h*(t-pi) ?

The solution to expand 3cos(t)h*(t-pi) is 3thcos(t)-3pihcos(t)

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expand 3cos(t)h*(t-pi)

expand

3 cos (t) h \cdot (t - π)

3 t h cos (t) - 3 πh cos (t)

Solution steps

3 cos (t) h (t - π)

= 3 h cos (t) (t - π)

Apply the distributive law:

a (b - c) = ab - a c

a = 3 cos (t) h, b = t, c = π

= 3 cos (t) h t - 3 cos (t) hπ

= 3 t h cos (t) - 3 πh cos (t)

2 \cdot (ln (x) - (\frac{1}{4}) \cdot e^{x}) \cdot (\frac{1}{x} - (\frac{1}{4}) \cdot e^{x})

(cos (θ) - x)^{2} + sin^{2} (θ)

\frac{2 x + 1}{x ( x + 1 ) ( x ^{2} + 4 x + 6 )}

(1 + e^{i x})^{2}

- 2 u sin (t) (t - π)

What is expand 3cos(t)h*(t-pi) ?
The solution to expand 3cos(t)h*(t-pi) is 3thcos(t)-3pihcos(t)