What is 2t(x)x^2+2t(x)+(t(x)^4+1)(d^2)/(dtdx)(x) ?

The solution to 2t(x)x^2+2t(x)+(t(x)^4+1)(d^2)/(dtdx)(x) is 2tx^3+2tx+(tx^4+1)(d^2)/(dtdx)(x)

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simplify 2t(x)x^2+2t(x)+(t(x)^4+1)(d^2)/(dtdx)(x)

simplify

2 t (x) x^{2} + 2 t (x) + (t (x)^{4} + 1) \frac{d ^{2}}{d t d x} (x)

2 t x^{3} + 2 t x + (t x^{4} + 1) \frac{d ^{2}}{d t d x} (x)

Solution steps

2 t (x) x^{2} + 2 t (x) + (t x^{4} + 1) \frac{d ^{2}}{d t d x} (x)

Remove parentheses:

(a) = a

= 2 t x x^{2} + 2 t x + (t x^{4} + 1) \frac{d ^{2}}{d t d x} (x)

2 t x x^{2} = 2 t x^{3}

= 2 t x^{3} + 2 t x + (t x^{4} + 1) \frac{d ^{2}}{d t d x} (x)

\frac{( x + 7 ) ( x - 3 )}{x ^{2}}

(y + \frac{5}{6})^{2}

(x + y + z)^{3}

\frac{1}{( T s + 1 ) ( s ^{2} )}

7 (x - \frac{1}{2})

What is 2t(x)x^2+2t(x)+(t(x)^4+1)(d^2)/(dtdx)(x) ?
The solution to 2t(x)x^2+2t(x)+(t(x)^4+1)(d^2)/(dtdx)(x) is 2tx^3+2tx+(tx^4+1)(d^2)/(dtdx)(x)