What is expand ((x+7)(x-3))/(x^2) ?

The solution to expand ((x+7)(x-3))/(x^2) is 1+4/x-(21)/(x^2)

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expand ((x+7)(x-3))/(x^2)

expand

\frac{( x + 7 ) ( x - 3 )}{x ^{2}}

1 + \frac{4}{x} - \frac{21}{x ^{2}}

Solution steps

\frac{( x + 7 ) ( x - 3 )}{x ^{2}}

Expand

(x + 7) (x - 3) : x^{2} + 4 x - 21

= \frac{x ^{2} + 4 x - 21}{x ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} + 4 x - 21}{x ^{2}} = \frac{x ^{2}}{x ^{2}} + \frac{4 x}{x ^{2}} - \frac{21}{x ^{2}}

= \frac{x ^{2}}{x ^{2}} + \frac{4 x}{x ^{2}} - \frac{21}{x ^{2}}

Apply rule

\frac{a}{a} = 1

\frac{x ^{2}}{x ^{2}} = 1

= 1 + \frac{4 x}{x ^{2}} - \frac{21}{x ^{2}}

Cancel

\frac{4 x}{x ^{2}} : \frac{4}{x}

= 1 + \frac{4}{x} - \frac{21}{x ^{2}}

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\frac{1}{( T s + 1 ) ( s ^{2} )}

7 (x - \frac{1}{2})

y (5 x + 3 y - 3 z = 0,) (2 x + y - 3 z = 1)

What is expand ((x+7)(x-3))/(x^2) ?
The solution to expand ((x+7)(x-3))/(x^2) is 1+4/x-(21)/(x^2)