What is expand (8z)/((z-2)(z+1)) ?

The solution to expand (8z)/((z-2)(z+1)) is (8z)/(z^2-z-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (8z)/((z-2)(z+1))

expand

\frac{8 z}{( z - 2 ) ( z + 1 )}

\frac{8 z}{z ^{2} - z - 2}

Solution steps

\frac{8 z}{( z - 2 ) ( z + 1 )}

Expand

(z - 2) (z + 1) : z^{2} - z - 2

= \frac{8 z}{z ^{2} - z - 2}

(6 - 2 x + 1)^{2}

\frac{( x + 3 ) ( x - 7 )}{( x + 4 ) ( x - 5 )}

\frac{x + 2}{( x - 4 ) ( x - 2 )}

\frac{4 b ( a b ^{2} - a ^{5} )}{( a ^{4} + b ^{2} ) ^{2}}

\frac{8640 e ^{- 0.96 t}}{( 1 + 3 e ^{- 0.96 t} ) ^{2}}

What is expand (8z)/((z-2)(z+1)) ?
The solution to expand (8z)/((z-2)(z+1)) is (8z)/(z^2-z-2)