What is expand ((-2x+2)^3)/3 ?

The solution to expand ((-2x+2)^3)/3 is -(8x^3)/3+8x^2-8x+8/3

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expand ((-2x+2)^3)/3

expand

\frac{( - 2 x + 2 ) ^{3}}{3}

- \frac{8 x ^{3}}{3} + 8 x^{2} - 8 x + \frac{8}{3}

Solution steps

\frac{( - 2 x + 2 ) ^{3}}{3}

(- 2 x + 2)^{3} = - 8 x^{3} + 24 x^{2} - 24 x + 8

= \frac{( - 8 x ^{3} + 24 x ^{2} - 24 x + 8 )}{3}

Remove parentheses:

(- a) = - a

= \frac{- 8 x ^{3} + 24 x ^{2} - 24 x + 8}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 8 x ^{3} + 24 x ^{2} - 24 x + 8}{3} = - \frac{8 x ^{3}}{3} + \frac{24 x ^{2}}{3} - \frac{24 x}{3} + \frac{8}{3}

= - \frac{8 x ^{3}}{3} + \frac{24 x ^{2}}{3} - \frac{24 x}{3} + \frac{8}{3}

Divide the numbers:

\frac{24}{3} = 8

= - \frac{8 x ^{3}}{3} + 8 x^{2} - 8 x + \frac{8}{3}

\frac{x ^{3} - 4 x ^{2} + 4}{( - x + 3 ) ( x + 3 )}

A l e f t (A + B)

(e^{2 x} + e^{- 2 x}) (2 e^{2 x} + 2 e^{- 2 x})

\frac{1}{( 1 - x ) ( k x ) ^{0.5}}

- \frac{2 x + 1}{( 1 + x + x ^{2} ) ^{2}}

What is expand ((-2x+2)^3)/3 ?
The solution to expand ((-2x+2)^3)/3 is -(8x^3)/3+8x^2-8x+8/3