What is (a/3-b/2)(a/3+b/2) ?

The solution to (a/3-b/2)(a/3+b/2) is ((2a-3b)(2a+3b))/(36)

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simplify (a/3-b/2)(a/3+b/2)

simplify

(\frac{a}{3} - \frac{b}{2}) (\frac{a}{3} + \frac{b}{2})

\frac{( 2 a - 3 b ) ( 2 a + 3 b )}{36}

Solution steps

(\frac{a}{3} - \frac{b}{2}) (\frac{a}{3} + \frac{b}{2})

Simplify

\frac{a}{3} - \frac{b}{2} : \frac{2 a - 3 b}{6}

= \frac{2 a - 3 b}{6} (\frac{a}{3} + \frac{b}{2})

Simplify

\frac{a}{3} + \frac{b}{2} : \frac{2 a + 3 b}{6}

= \frac{2 a - 3 b}{6} \cdot \frac{2 a + 3 b}{6}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 2 a - 3 b ) ( 2 a + 3 b )}{6 \cdot 6}

Multiply the numbers:

6 \cdot 6 = 36

= \frac{( 2 a - 3 b ) ( 2 a + 3 b )}{36}

(x - \frac{25}{8})^{2}

- 5 [(x^{3} + 1) (x + 4)]

(x - 2 + 2)^{2}

cos (2) (π - θ)

x^{\frac{1}{3}} (4 x - 4)

What is (a/3-b/2)(a/3+b/2) ?
The solution to (a/3-b/2)(a/3+b/2) is ((2a-3b)(2a+3b))/(36)