What are the solutions to the equation 3(x+1)^2=36 ?

The solutions to the equation 3(x+1)^2=36 are x=2sqrt(3)-1,x=-2sqrt(3)-1

Find the zeros of 3(x+1)^2=36

The zeros of 3(x+1)^2=36 are x=2sqrt(3)-1,x=-2sqrt(3)-1

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3 (x + 1)^{2} = 36

x = 23 - 1, x = - 23 - 1

Solution steps

3 (x + 1)^{2} = 36

Divide both sides by

3

(x + 1)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 12 : x = 23 - 1

Solve

x + 1 = - 12 : x = - 23 - 1

The solutions to the quadratic equation are:

x = 23 - 1, x = - 23 - 1

1 + 4 x^{2} = 0

8 y^{2} + 6 y - 9

z^{2} + 2 z - 4 = 0

5 c^{2} + 7 c + 1 = 2 c

q^{2} + 34 = 35

What are the solutions to the equation 3(x+1)^2=36 ?
The solutions to the equation 3(x+1)^2=36 are x=2sqrt(3)-1,x=-2sqrt(3)-1
Find the zeros of 3(x+1)^2=36
The zeros of 3(x+1)^2=36 are x=2sqrt(3)-1,x=-2sqrt(3)-1