What is expand-(8sin(θ))/((2-cos(θ))^2) ?

The solution to expand-(8sin(θ))/((2-cos(θ))^2) is -(8sin(θ))/(4-4cos(θ)+cos^2(θ))

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expand-(8sin(θ))/((2-cos(θ))^2)

expand

- \frac{8 sin ( θ )}{( 2 - cos ( θ ) ) ^{2}}

- \frac{8 sin ( θ )}{4 - 4 cos ( θ ) + cos ^{2} ( θ )}

Solution steps

- \frac{8 sin ( θ )}{( 2 - cos ( θ ) ) ^{2}}

(2 - cos (θ))^{2} = 4 - 4 cos (θ) + cos^{2} (θ)

= - \frac{8 sin ( θ )}{cos ^{2} ( θ ) - 4 cos ( θ ) + 4}

\frac{4 s + 1}{s ( 2 s + 1 ) ( s + 1 )}

\frac{( x - 0 ) ( x - 1 ) ( x - 4 )}{- 4}

(\frac{1}{x ^{2}} + y^{3})^{4}

(1 + 2 x^{3}) e^{x^{2}}

- 9 (5 + 3 h - 4 i)

What is expand-(8sin(θ))/((2-cos(θ))^2) ?
The solution to expand-(8sin(θ))/((2-cos(θ))^2) is -(8sin(θ))/(4-4cos(θ)+cos^2(θ))