What is expand-sin(3x^2+3x)(6x+3) ?

The solution to expand-sin(3x^2+3x)(6x+3) is -6xsin(3x^2+3x)-3sin(3x^2+3x)

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expand-sin(3x^2+3x)(6x+3)

expand

- sin (3 x^{2} + 3 x) (6 x + 3)

- 6 x sin (3 x^{2} + 3 x) - 3 sin (3 x^{2} + 3 x)

Solution steps

- sin (3 x^{2} + 3 x) (6 x + 3)

Apply the distributive law:

a (b + c) = ab + a c

- sin (3 x^{2} + 3 x) (6 x + 3) = - sin (3 x^{2} + 3 x) \cdot 6 x - sin (3 x^{2} + 3 x) \cdot 3

= - sin (3 x^{2} + 3 x) \cdot 6 x - sin (3 x^{2} + 3 x) \cdot 3

= - 6 x sin (3 x^{2} + 3 x) - 3 sin (3 x^{2} + 3 x)

\frac{5 ( z ^{4} + z ^{3} + z ^{2} + z + 1 )}{z ^{3} ( 5 z - 1 )}

lo g_{10} (3) (x^{2} + 1)

- 6 (3 e^{3 x} cos (2 x) - 2 e^{3 x} sin (2 x))

(21) (2 x + y, x)

l im x \Rightarrow 1 (x^{2} - x) sin (x - 1)

What is expand-sin(3x^2+3x)(6x+3) ?
The solution to expand-sin(3x^2+3x)(6x+3) is -6xsin(3x^2+3x)-3sin(3x^2+3x)