What is expand (8(3x^2+4))/((x^2-4)^3) ?

The solution to expand (8(3x^2+4))/((x^2-4)^3) is (24x^2+32)/(x^6-12x^4+48x^2-64)

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expand (8(3x^2+4))/((x^2-4)^3)

expand

\frac{8 ( 3 x ^{2} + 4 )}{( x ^{2} - 4 ) ^{3}}

\frac{24 x ^{2} + 32}{x ^{6} - 12 x ^{4} + 48 x ^{2} - 64}

Solution steps

\frac{8 ( 3 x ^{2} + 4 )}{( x ^{2} - 4 ) ^{3}}

(x^{2} - 4)^{3} = x^{6} - 12 x^{4} + 48 x^{2} - 64

= \frac{8 ( 3 x ^{2} + 4 )}{x ^{6} - 12 x ^{4} + 48 x ^{2} - 64}

Expand

8 (3 x^{2} + 4) : 24 x^{2} + 32

= \frac{24 x ^{2} + 32}{x ^{6} - 12 x ^{4} + 48 x ^{2} - 64}

\frac{1}{3} H (t - 6) - \frac{1}{3} e^{- 3 (t - 6)}

\frac{20 ( s + 1 ) ( s + 2 )}{s ^{2} + 32 s + 40}

(x - 4) (x - 6) (x + 7)

\frac{π}{18} (2 sin (7 x) \cdot cos (2 x) - sin (5 x))

\frac{u ^{2} x - u ^{2} x ^{2} - 1}{u ^{4} ( x ^{2} - x ^{3} )}

What is expand (8(3x^2+4))/((x^2-4)^3) ?
The solution to expand (8(3x^2+4))/((x^2-4)^3) is (24x^2+32)/(x^6-12x^4+48x^2-64)