What is x^2((16)/x-x/4) ?

The solution to x^2((16)/x-x/4) is (x(64-x^2))/4

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simplify x^2((16)/x-x/4)

simplify

x^{2} (\frac{16}{x} - \frac{x}{4})

\frac{x ( 64 - x ^{2} )}{4}

Solution steps

x^{2} (\frac{16}{x} - \frac{x}{4})

Join

\frac{16}{x} - \frac{x}{4} : \frac{64 - x ^{2}}{4 x}

= x^{2} \frac{64 - x ^{2}}{4 x}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{x ^{2} ( 64 - x ^{2} )}{4 x}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{xx ( 64 - x ^{2} )}{4 x}

Cancel the common factor:

x

= \frac{x ( 64 - x ^{2} )}{4}

x + 5 \cdot (- x - 5)

(m v - v) (m d v + v d m)

\times (\times + 4 y)

\frac{d}{d v} ((p) ((p + \frac{5}{v ^{2}}) (v - 3.1)))

(\frac{3 a + b}{4})^{2} - (\frac{b ^{2} + ba + a ^{2}}{2})