What is expand (x^4+10x^3+23x^2+14x)/4 ?

The solution to expand (x^4+10x^3+23x^2+14x)/4 is (x^4)/4+(5x^3)/2+(23x^2)/4+(7x)/2

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expand (x^4+10x^3+23x^2+14x)/4

expand

\frac{x ^{4} + 10 x ^{3} + 23 x ^{2} + 14 x}{4}

\frac{x ^{4}}{4} + \frac{5 x ^{3}}{2} + \frac{23 x ^{2}}{4} + \frac{7 x}{2}

Solution steps

\frac{x ^{4} + 10 x ^{3} + 23 x ^{2} + 14 x}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{4} + 10 x ^{3} + 23 x ^{2} + 14 x}{4} = \frac{x ^{4}}{4} + \frac{10 x ^{3}}{4} + \frac{23 x ^{2}}{4} + \frac{14 x}{4}

= \frac{x ^{4}}{4} + \frac{10 x ^{3}}{4} + \frac{23 x ^{2}}{4} + \frac{14 x}{4}

Cancel

\frac{10 x ^{3}}{4} : \frac{5 x ^{3}}{2}

= \frac{x ^{4}}{4} + \frac{5 x ^{3}}{2} + \frac{23 x ^{2}}{4} + \frac{14 x}{4}

Cancel

\frac{14 x}{4} : \frac{7 x}{2}

= \frac{x ^{4}}{4} + \frac{5 x ^{3}}{2} + \frac{23 x ^{2}}{4} + \frac{7 x}{2}

\frac{5 - x}{( x + 6 ) ( x ^{2} + 1 )}

(\frac{2 x ^{2} y ^{2}}{3} + 2) (x y + 4 x)

\frac{d}{d x} ((x - 1) (x - 7)^{3}) + 10

(2 + 4 - x^{2} - y^{2})^{2}

- \frac{r ( a - bk )}{b c k}

What is expand (x^4+10x^3+23x^2+14x)/4 ?
The solution to expand (x^4+10x^3+23x^2+14x)/4 is (x^4)/4+(5x^3)/2+(23x^2)/4+(7x)/2