What is i(2+3i)(c+di) ?

The solution to i(2+3i)(c+di) is (-2d-3c)+(2c-3d)i

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simplify i(2+3i)(c+di)

simplify

i (2 + 3 i) (c + d i)

(- 2 d - 3 c) + (2 c - 3 d) i

Solution steps

i (2 + 3 i) (c + d i)

Apply complex arithmetic rule:

(a + bi) (c + d i) = (a c - b d) + (a d + b c) i

= i ((2 c - 3 d) + (2 d + 3 c) i)

Expand

i ((2 c - 3 d) + (2 d + 3 c) i) : 2 c i - 3 d i - 2 d - 3 c

= 2 c i - 3 d i - 2 d - 3 c

Rewrite in standard complex form:

(- 2 d - 3 c) + (2 c - 3 d) i

= (- 2 d - 3 c) + (2 c - 3 d) i

(64 t^{3} - 128 t^{2} + 64 t) \cdot 42

2 (2 y^{2} + \frac{2}{y ^{2}} + c)

\frac{( x - 9 y ) ( x - 5 y )}{2 ( x + y )}

(4 x - 5) (6 x + 4)

(\frac{a x}{3} - b y) (\frac{a x}{3} + b y)